10x^2+2510x=0

Solution for 10x^2+2510x=0 equation:

10x^2+2510x=0

a = 10; b = 2510; c = 0;
Δ = b2-4ac
Δ = 25102-4·10·0
Δ = 6300100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6300100}=2510$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2510)-2510}{2*10}=\frac{-5020}{20}
=-251
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2510)+2510}{2*10}=\frac{0}{20}
=0
$